A 1.5 liter flask is filled with nitrogen at a pressure of 12 atmospheres. What size flask would be required to hold this gas at a pressure of 2.0 atmospheres?

1 Answer
Jun 13, 2017

Answer:

#9.0# #"L"#

Explanation:

To solve this equation, we can use the pressure-volume relationship of gases, illustrated by Boyle's law:

#P_1V_1 = P_2V_2# (with constant temperature)

Since we need to find the final volume, let's rearrange this equation to solve for #V_2#:

#V_2 = (P_1V_1)/(P_2)#

Our known variables are

  • #P_1# - #12# #"atm"#

  • #V_1# - #1.5# #"L"#

  • #P_2# - #2.0# #"atm"#

Plugging these into the equation we have

#V_2 = ((12cancel("atm"))(1.5"L"))/(2.0cancel("atm")) = color(red)(9.0# #color(red)("L"#

Thus, when a #1.5#-liter flask containing gas with a pressure of #12# atmospheres is subjected to a decrease in pressure to #2.0# atmospheres, at constant temperature the volume will expand to #color(red)(9.0# liters.