A 2.0 kg softball is pitched to you at 20 m/s. You hit the ball back along the same path, and at the same speed. If the bat was in contact with the ball for 0.10 s, what is the average force the bat exerted?

1 Answer
Jane
Mar 4, 2018

#800N#

Explanation:

Average force exerted during this collision is the rate of change in momentum of the softball.

So,change in momentum of the ball is, #m(v-u)=2(20-(-20)=80 Kgms^-1# (considering direction of the velocity of the softball after collision to be positive)

So,average force applied was #80/0.10=800N#

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