A 24 kg crate, initially at rest on a horizontal surface, requires a 63 N horizontal force to set it in motion. Once in motion, a horizontal force of 47 N is required to keep it moving at constant speed. What is the coefficient of static friction?

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Answer 1 · 2018-01-14T07:43:31

The coefficient of static friction is #=0.26#

#"Static friction is the resistance to movement when two non-moving"#

#"solid objects are in contact with one another. Static friction matches"#

#"applied force and prevents movement. When the applied force "#
#"overcomes static friction, the object starts moving, and at this"#

#"point, static friction ceases and kinetic friction comes into play."#

The mass of the crate is #m=24kg#

The normal force is #N=24gN#

The coefficient of static friction is

#mu_s=F_s/N=60/(24g)=0.26#

The coefficient of kinetic friction is

#mu_k=F_k/N=47/(24g)=0.20#

Therefore,

# mu_k < mu_s #