# A 29.80 g sample of liquid cadmium at 377.00°C is poured into a mold and allowed to cool to 24.00°C. How many kJ of energy are released in this process?

##
The following information is given for cadmium at 1atm:

Tb = 765.00°C Hvap (765.00°C) =889.6 J/g

Tm = 321.00°C Hfus (321.00°C) = 54.40 J/g

Specific heat solid = 0.2300 J/g °C

Specific heat liquid = 0.2640 J/g °C

(Report the answer as a positive number.)

Energy= kJ

The following information is given for cadmium at 1atm:

Tb = 765.00°C Hvap (765.00°C) =889.6 J/g

Tm = 321.00°C Hfus (321.00°C) = 54.40 J/g

Specific heat solid = 0.2300 J/g °C

Specific heat liquid = 0.2640 J/g °C

(Report the answer as a positive number.)

Energy= kJ

##### 1 Answer

The total energy released is 4097 J (to four sig. digits) or 4.097 kJ

#### Explanation:

Since you calcium starts this process at 377 °C and is in liquid phase, the heat of vapourization does not enter into this. However, the heat of fusion does, as the calcium will freeze into a solid before it reaches 24 °C

So, three things happen, each of which involves a quantity of heat.

First, the liquid calcium cools from 377 °C to 321 °C. Since the specific heat for the liquid is 0.2640 J/g °C, this heat is

where

Second, the liquid freezes at 321 °C:.

Finally, the solid cools. The calculation is similar to the first one above:

(notice the change to the specific heat of the solid, and the large drop in temperature, from 321 ° to 24 °)

Total energy is the sum: