# A 3.0 mL sample of HNO_3 solution is exactly neutralized by 6.0 mL of .50 M KOH. What is the molarity of the HNO_3 solution?

Apr 25, 2016

$6.0 m L \times \frac{1 L}{1000 m L} \times 0.50 \frac{m o l}{L} = 3.0 \times {10}^{-} 3 m o l$
This must be equal to the number of moles of $H N {O}_{3}$, so the concentration of that solution must be:
$\frac{3.0 \times {10}^{-} 3 m o l}{3.0 m L} \times \frac{1000 m L}{1 L} = 1.0 \frac{m o l}{L}$