Question

A 3.76 g sample of a noble gas is stored in a 2.00 L vessel at 874 torr and 25°C. What is the noble gas?

Answer 1

Argon

Explanation:

We need to solve for the molar mass of the gas in `g/"mol"`:

R constants (at least one should be given to you):
`62.4 ("L torr")/(molK)`

`0.0821("L atm")/(molK)`

`8.31 ("L KPa")/(molK)`

`62.4 ("L mmHg")/(molK)`

Dimensional analysis:
`3.76 "g"* (62.4cancel" L" cancel("torr"))/("mol"cancel( "K"))* (298 cancel("K"))/ (874 cancel("torr"))*1/(2 cancel"L")="40.0 g/mol Noble Gas"`

This is the molar mass of Argon