Question

A 3kΩ resistor has a current of 0.002A flowing through it. what is the potential difference?

Answer 1

I get `6` volts.

Explanation:

The potential difference of a circuit is the same thing as the voltage of the circuit. So, we can use Ohm's Law here, which states that,

`V=IR`

• `V` is the voltage in volts `("V")`

• `I` is the current flowing in amperes `("A")`

• `R` is the resistance of the circuit in ohms `(Omega)`

We got: `3kOmega=3000 \ Omega`, and so:

`V=3000 \ Omega*0.002 \ "A"`

`=6 \ "V"`