A #5.0# #kg# bucket of water is raised from a well by a rope. If the upward acceleration of the bucket is #3.0# #m##/s^2#, what is the force exerted by the rope on the bucket of water?

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Answer 1 · 2017-05-08T09:44:49

The force exerted by the rope is #=64N#

Resolving in the vertical direction #uarr^+#

Let the tension in the rope de #=TN#

Then,

#T-mg=ma#

#T=ma+mg=m(a+g)#

#=5(3+9.8)#

#=64N#