Question

A 7.5 M sodium sulfate in 12 mL?

Answer 1

`0.09` moles of sodium sulfate or `~~12.8` grams of sodium sulfate.

Explanation:

We can find the amount of sodium sulfate by taking the concentration of the solution, and then multiplying by the volume.

The equation is:

`n=c*v`

• `n` is the number of moles of substance

• `c` is the concentration of the solution in terms of molarity

• `v` is the volume, preferrably in liters

So here, we get:

`n=(7.5 \ "mol")/(color(red)cancelcolor(black)"L")*0.012 \ color(red)cancelcolor(black)"L"`

`=0.09 \ "mol"`

Now, if we want to find the amount of mass of this sample, we simply multiply by sodium sulfate's molar mass and get:

`0.09color(red)cancelcolor(black)"mol"*stackrel("molar mass of" \ Na_2SO_4)overbrace((142.04 \ "g")/(color(red)cancelcolor(black)"mol"))~~12.8 \ "g"`