Question

A 7 liter balloon at 22°C is carried outside where the temperature is -3°C. What is its new volume?

Answer 1

Reduced somewhat.

Explanation:

Charles' Law holds that `VpropT` at constant `"pressure"`, and where #"absolute temperature is quoted.

Since `V=kT`, `V_1/T_1=V_2/T_2`, and `V_2=V_1/T_1xxT_2`

`=` `(7*L)/(295*cancelK)xx270*cancelK` `~=` `6*L`