A bag contains 12 sweets, of which 5 are red, 4 are green and 3 are yellow. 3 sweets are chosen without replacement. What is the probability that he chooses no red sweets?
1 Answer
Jun 30, 2018
Explanation:
For:
#12 = {(5R),(4G ),(3Y ):}#
There are
There are
So:
Alternatively, using the Hypergeometric distribution:

#P(X = k) = (((K),(k)) ((NK),(nk)))/(((N),(n)))# 
#N = 12# , is the population size (ie, # balls): #K= 5# , is the number of success states (ie, #Red balls) in the population,#n= 3# , is the number of draws#k= 0# , is the number of observed successes