Question

A ball is thrown (from rest) from a tall building. After 3 seconds. What is the velocity ?

Answer 1

`"29.4 m/s"`

Explanation:

`v = u + at`

In above equation,

• `v` = Velocity of ball at time `t`

• `u` = Initial velocity of ball

• `a` = Acceleration of ball (`= "9.8 m/s"^2`)

• `t` = time

`v = ("0 m/s") + ("9.8 m/s"^2 × "3 s") = "29.4 m/s"`