A ball is thrown horizontally at a speed of 20 m/s from the top of a cliff. How long does the ball take to fall 19.6 m to the ground?

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Answer 1 · 2016-12-13T08:13:34

The answer is #=2s#

The time taken is given by the equation

#y=v_(y0)t+1/2g t^2 #

The vertical component of the velicity #=v_(y0)=0#

And #y=19.6 m#

#g=9.8ms^(-2)#

So,

#19.6=0+1/2*9.8*t^2#

#t^2=19.6*2/9.8=4#

#t=2s#