A ball with a mass of #144 g# is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of #96 (kg)/s^2# and was compressed by #4/3 m# when the ball was released. How high will the ball go?

1 Answer
Dec 7, 2017

Answer:

The height is #=60.5m#

Explanation:

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The spring constant is #k=96kgs^-2#

The compression is #x=4/3m#

The potential energy is

#PE=1/2*96*(4/3)^2=85.33J#

This potential energy will be converted to kinetic energy when the spring is released and to potential energy of the ball

#KE_(ball)=1/2m u^2#

Let the height of the ball be #=h #

The acceleration due to gravity is #g=9.8ms^-2#

Then ,

The potential energy of the ball is #PE_(ball)=mgh#

Mass of the ball is #m=0.144kg#

#PE_(ball)=85.33=0.144*9.8*h#

#h=85.33*1/(0.144*9.8)#

#=60.5m#

The height is #=60.5m#