A ball with a mass of #450 g# is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of #15 (kg)/s^2# and was compressed by #8/3 m# when the ball was released. How high will the ball go?

1 Answer
Aug 7, 2017

Answer:

The height is #=12.09m#

Explanation:

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The spring constant is #k=15kgs^-2#

The compression is #x=8/3m#

The potential energy in the spring is

#PE=1/2*15*(8/3)^2=53.33J#

This potential energy will be converted to kinetic energy when the spring is released and to potential energy of the ball

#KE_(ball)=1/2m u^2#

Let the height of the ball be #=h #

Then ,

The potential energy of the ball is #PE_(ball)=mgh#

#PE_(ball)=53.33=0.450*9.8*h#

#h=53.33*1/(0.450*9.8)#

#=12.09m#