A ball with a mass of #480 g# is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of #16 (kg)/s^2# and was compressed by #3/5 m# when the ball was released. How high will the ball go?

Question

1263 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-02-01T16:15:05

The height is #=0.61m#

enter image source here

The spring constant is #k=16kgs^-2#

The compression is #x=3/5m#

The potential energy is

#PE=1/2*16*(3/5)^2=2.88J#

This potential energy will be converted to kinetic energy when the spring is released and to potential energy of the ball

#KE_(ball)=1/2m u^2#

Let the height of the ball be #=h #

The sacceleration due to gravity is #g=9.8ms^-2#

Then ,

The potential energy of the ball is #PE_(ball)=mgh#

Mass of the ball is #m=0.48kg#

#PE_(ball)=5.76=0.48*9.8*h#

#h=2.88*1/(0.48*9.8)#

#=0.61m#

The height is #=0.61m#