A ball with a mass of 480 g is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of 24 (kg)/s^2 and was compressed by 8/9 m when the ball was released. How high will the ball go?

1 Answer
Sep 29, 2017

6.28 m/s

Explanation:

If Spring compressed by x then Potential Energy stored in it
U=1/2kx^2
k="spring constant" =24 (kg)/s^2
x="Displacement "=8/9 m

U=1/2(24)(8/9)^2=(24xx64)/(2xx81)=9.48 J

After Release spring loaded contraption Potential Energy Changes into Kinetic Energy. (Conservation of Energy)
Hence Mass of 480g has Kinetic Energy 1/2mv^2

Now Using Conservation of Energy
"Kinetic Energy"="Potential Energy"
U=1/2mv^2
9.48=1/2(0.48)(v)^2
v^2=39.50
v=sqrt39.50
v=6.28 m/s