# A ball with a mass of 50 g is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of 16 (kg)/s^2 and was compressed by 2/5 m when the ball was released. How high will the ball go?

Mar 5, 2018

2.56 m

#### Explanation:

Acoording to energy conservation,
$\text{gain in potential energy of the ball"="loss of energy stored in the compressed spring}$
thus,
$\frac{1}{2} \times k \times {\left(x\right)}^{2} = m \times g \times h$
or,$h = \frac{16 \times 4}{25}$ {on simplification}
$h$ comes out to be 2.56 metres