A ball with a mass of #70 g# is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of #19 (kg)/s^2# and was compressed by #7/6 m# when the ball was released. How high will the ball go?

1 Answer
Apr 10, 2018

Answer:

The height reached by the ball is #=2.57m#

Explanation:

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The spring constant is #k=19kgs^-2#

The compression of the spring is #x=7/6m#

The potential energy stored in the spring is

#PE=1/2*19*(7/6)^2=12.93J#

This potential energy will be converted to kinetic energy when the spring is released and to potential energy of the ball

#KE_(ball)=1/2m u^2#

Let the height of the ball be #=h #

The acceleration due to gravity is #g=9.8ms^-2#

Then ,

The potential energy of the ball is #PE_(ball)=mgh#

Mass of the ball is #m=0.070kg#

#PE_(ball)=12.93=0.070*9.8*h#

#h=12.93*1/(0.07*9.8)#

#=1.22m#

The height reached by the ball is #=2.57m#