A balloon has a volume of 0.5 L at 20°C. What will the volume be if the balloon is heated to 150°C?

Assume constant pressure and mass.

2 Answers
Dec 26, 2016

Answer:

Assuming pressure is constant:

Explanation:

#V_1/T_1=V_2/T_2# (#T# in Kelvin)

#20^(o)C=20+273=293K#
#150^(o)C=150+273=423K#

#0.5/293=V_2/423->V_2=(0.5xx423)/293=0.72L#

Dec 26, 2016

Answer:

The new volume will be #"0.7 L"#.

Explanation:

This is an example of Charles' law, sometimes called the temperature-volume law. It states that the volume of a gas is directly proportional to the Kelvin temperature, while pressure and amount are held constant.

The equation is #V_1/T_1=V_2/T_2#, where #V# is volume and #T# is temperature in Kelvins.

Known
#V_1="0.5 L"#
#T_1="20"^@"C"+273.15="293 K"#
#T_2="150"^@"C"+273.15="423 K"#

Unknown
#V_2#

Solution
Rearrange the equation to isolate #V_2#. Substitute the known values into the equation and solve.

#V_2=(V_1T_2)/T_1#

#V_2=((0.5"L"xx423"K"))/(293"K")="0.7 L"# rounded to one significant figure