# A balloon has a volume of 20.0 L at atmospheric pressure and 20.0 C. One wants to increase the volume to 24.0 L at constant pressure. To what temperature in degrees Celsius does one need to increase the temperature to?

Aug 6, 2016

#### Explanation:

As the initial volume of 20 L is less than the final volume of 24 L, the temperature must increase.

This is based on Charles' Law, which states that there is a direct relationship between temperature and volume.

It is important to remember that Charles' Law is based on Kelvin temperatures.

Step one is to change Celsius degrees into kelvins.

$\text{0 °C" = "273 K}$

${T}_{1} = \text{(20 + 273) K" = "293 K}$

Step two is to insert the values into the Charles' Law expression.

${T}_{1} / {V}_{1} = {T}_{2} / {V}_{2}$

$\text{293 K"/"20 L" = T_2/"24 L}$

 24 × "293 K"/20 = T_2

$\text{352 K} = {T}_{2}$

Step three is to convert the Kelvin temperature to Celsius.

To change this answer back to Celsius degrees, subtract 273.

$\text{(352-273) °C"color(white)(l) =color(white)(l) "79 °C}$