A baseball is thrown from a stadium seat and its path is shown by h(t)=-16t^2+75, where h is height in feet and t is time in seconds. A. How long before the ball hits the ground. Round to hundredths B. How high off the ground is the stadium seat?

Question

1577 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-02-07T15:40:28

a. #2.16 s#

b. #75 ft#

The given equation is #h= -16t^2 +75#

You can compare this,with #s=-1/2g t^2#

So,putting #t=0#,we get, #h=75 ft# that means at the beginning of its journey,the baseball was #75 ft# above the ground

And it is given that the baseball was thrown from the stadium seat,that means the stadium seat lies #75 ft# above the ground.

Now, when you write, #h=0# in the given equation,the value of #t# means the time required for the baseball to reach the ground.

So,our equation becomes, #0 = -16t^2 +75#

or, #t=2.16 s#

So,after #2.16 s# of dropping the baseball,it will reach the ground.