A beg contains 4 white , 5 red and 6 green ball . Three balls are drawn at random . What is the chance that a white , a red and a green ball is drawn ?
2 Answers
Explanation:
Let's first see how many balls there are in total.
So, for the first draw, you want to draw a white ball.
You want the next ball to be red. Since one has been drawn, only
Finally, you want a green ball. Since two have been drawn, only
The total probability is
Probability of taking one White, one Red and one Green ball
Explanation:
Give -
White Balls
Red Balls
Green Balls
Total
Probability of taking one White, one Red and one Green ball
#=(""^4C_1xx""^5C_1 xx ""^6C_1)/(""^15C_3)#
#=(4 xx 5 xx 6)/455=120/455=24/91#