A bicycle wheel has an outside radius of 35.0 cm. If the bicycle is traveling at a speed of 30.0 km/h, what is the period of rotation of the wheel? Physics 1 Answer ali ergin Feb 2, 2018 "Period of wheel :0.26 " "sec. Explanation: "circumference of the bicycle wheel can be calculated using ""formula "s=2 pi r s=2*pi*35=219.9cm=2.199m "We have to find out how many times the bicycle's wheel has""turned ." 30 km=30000meters. "n:number of revolution" n=30.000/(2.199)=13642.6 "How many seconds have passed since the wheel was turned ""once? we must answer the question." 1h=3600 sec. "T:Period" T=3600/(13642.6) T=0.26 sec Answer link Related questions How do I determine the molecular shape of a molecule? What is the lewis structure for co2? What is the lewis structure for hcn? How is vsepr used to classify molecules? What are the units used for the ideal gas law? How does Charle's law relate to breathing? What is the ideal gas law constant? How do you calculate the ideal gas law constant? How do you find density in the ideal gas law? Does ideal gas law apply to liquids? Impact of this question 1852 views around the world You can reuse this answer Creative Commons License