A block weighing 80 lb rests on a 30 degrees incline. What is the magnitude of the components of the block's weight perpendicular and parallel to the incline?

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Answer 1 · 2018-04-19T22:30:11

See below

#F_w= 80 lbs#

You can draw yourself a diagram, but here's what you can deduce:

To find force parallel to the incline:
#F_p= F_w*sin(30^@)#

To find force perpendicular to the incline:
#F_n= F_w*cos(30^@)#

#F_p= 80 lbs*sin(30^@)= 40 lbs.#
#F_n= 80*cos(30^@)= 40sqrt3 lbs.#

A block weighing 80 lb rests on a 30 degrees incline. What is the magnitude of the components of the​ block's weight perpendicular and parallel to the incline?