Question

A body is charged to a certain potential.When an additional charge of 60nC is imparted to it ,rise in potential is found to be 15 mV .Find the capacitance of the body?

Answer 1

`"4.0 μF"`

Explanation:

Capacitance is given as

`"C" = "Q"/"V"`

`"C" = (60 × 10^-9\ "C")/(15 × 10^-3\ "V") = 4.0 × 10^-6\ "F" = "4.0 μF"`