A body lying initially at point (3,7) starts moving with a constant acceleration of 4i. What is it's position after 3 seconds in co-ordinates?

1 Answer
Mar 20, 2018

#(21, 7)#

Explanation:

Along horizontal

#"S" = "ut" + 1/2\ "at"^2#

#"x’" = "(0 m/s × 3 s)" + (1/2 × "4 m/s"^2 × "(3 s)"^2) = "18 m"#

#"x = x’ + 3 = 18 + 3" = color(blue)21#

Along vertical

There is no acceleration along vertical. Therefore there is no displacement along this direction.

Conclusion: Position of body after #"3 s"# is #(21, 7)#