A box with an initial speed of #9 m/s# is moving up a ramp. The ramp has a kinetic friction coefficient of #5/4 # and an incline of #(3 pi )/4 #. How far along the ramp will the box go?

1 Answer
Feb 18, 2017

Answer:

The box will go #-23.36 m#etres along the ramp.

Explanation:

If a block is moving up the inclined plane then the distance travelled by the block up the plane is
#s={[u^2]/[2g(sintheta+mu_kcostheta)]}#
Assume box as block and ramp as inclined plane and also consider #g=9.8m//s^2#.
Calculating with given values,
#s={[9m//s]^2/[2xx(9.8m//s^2)xx[sin((3pi)/4)+(5/4)cos((3pi)/4)]]}#
#:.s=-23.36m#.
Here'#-#' sign denotes that the body is travelling up the incline plane.