A car accelerated #5# #m##/##s^2# for #380# #s#. What was its change in velocity?

1 Answer
Jan 15, 2018

The change in velocity is #=1900ms^-1#

Explanation:

The acceleration is uniform

#a=5ms^-2#

The time is

#t=380s#

Let the initial velocity be #=(u)ms^-1#

Let the final velocity be #=(u_1)ms^-1#

Apply the equation of motion

#u_1=u+at#

#Deltau=u_1-u=at#

#Deltau=5*380=1900ms^-1#