We are given the ratio #1" gallon" : 27" miles"#
which can also be written as #(1" gallon")/(27" miles")#
Travelling #2,727" miles"# at a ratio of #(1" gallon")/(27" miles")# requires:
#color(white)("XXX")color(red)(cancel(color(black)(2727)))^101color(blue)(cancel(color(black)(" miles"))) xx (1 " gallon")/(color(red)(cancel(color(black)(27)))color(blue)(cancel(color(black)(" miles"))))#
#color(white)("XXX")=101 " gallons"#
At a cost of #($4.04)/"gallon"# this would cost
#color(white)("XXX")($4.04)/color(green)(cancel(color(black)("gallon")))xx101 color(green)(cancel(color(black)(" gallons")))#
#color(white)("XXX")=$408.04#