A car enters the freeway with a speed of 6.4 m/s and accelerates uniformly for 3.2 km in 3.5 min. How fast (in m/s) is the car moving after this time?

1 Answer
Jul 22, 2016

#=24.076m/s#'

Explanation:

#u->"Initial velocity"=6.4m/s#

#s->"Distance covered"=3.2km=3200m#

#t->"Time taken"=3.5min=3.5xx60=210s#

#"Let "v " is the final velocity after 3.5min"#

Now we know for the body moving with uniform acceleration,the distance travelled is related with initial and final velocities and the time taken as follows.
#s=1/2(u+v)*t#

#=>3200=1/2*(6.4+v)*210#

#=>v=(6400/210-6.4)m/s=24.076m/s#