A car from stationary position accelerates uniformly over a time of 5.75 seconds and takes a distance of 34m. Determine the acceleration of the car. ??

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Answer 1 · 2018-07-12T05:49:20

The acceleration is #=2.057ms^-1#

The initial velocity is #u=0ms^-1#

The time is #t=5.75s#

The distance covered is #s=34m#

Aplly the equation of motion

#s=ut+1/2at^2#

Plugging in the above values, we get

#34=0+1/2a*5.75^2#

The acceleration is

#a=(2*34)/(5.75^2)=2.057ms^-1#