A car has a mass of 1,200 kg. What is its acceleration when the engine exerts a force of 600 N?

Jul 18, 2017

$0.5$ ${\text{m s}}^{- 2}$

Explanation:

Newton's second law of motion is mathematically expressed as $F = m a$; where $F$ is the force exerted on an object, $m$ is the mass of the object, and $a$ is the acceleration of that object.

In this case, the mass of the car and the force exerted on it are provided as information.

Let's plug in the values into the formula $F = m a$:

$R i g h t a r r o w 600$ $\text{N} = 1200$ $\text{kg} \times a$

Let's express $\text{N}$ using SI base units:

$R i g h t a r r o w 600$ ${\text{kg m s}}^{- 2} = 1200$ $\text{kg} \times a$

$R i g h t a r r o w \frac{600 \text{ kg m s"^(- 2))(1200 " kg") = frac(1200 " kg")(1200 " kg}}{\times} a$

$R i g h t a r r o w \frac{1}{2}$ ${\text{m s}}^{- 2} = 1 \times a$

$\therefore a = 0.5$ ${\text{m s}}^{- 2}$

Therefore, the acceleration of the car is $0.5$ ${\text{m s}}^{- 2}$ when its engine exerts a force of $600$ $\text{N}$.