A car starts from rest and moves a distance of 5m in t seconds,where s=1/6t^3+1/4t^2.what is its acceleration when t=0,t=2?
2 Answers
Jan 14, 2018
See the explanation below
Explanation:
I assume that
The acceleration is the second derivative of the distance, the first derivative is the velocity.
The velocity is
The acceleration is
Therefore,
When
When
I hope that this helps!!!!
Jan 14, 2018
Acceleration is
Acceleration is
Explanation:
Differentiate the given equation twice and you will get,acceleration of the car to be,
Now put the given time values it comes out to be 0.5