# A car with an initial speed of 6.5 m/s accelerates at a uniform rate of 0.92 m/s^2 for 3.6 s. What is the final speed and the displacement of the car during this time?

Mar 3, 2018

Use the equations of motion, Luke!

#### Explanation:

$S = u t + \left(\frac{1}{2}\right) a {t}^{2}$

$S = 6.5 + \left(\frac{1}{2}\right) \left(0.92\right) \left({3.6}^{2}\right)$

$S = 12.46$

${v}^{2} - {u}^{2} = 2 a S$

${v}^{2} - {\left(6.5\right)}^{2} \textcolor{w h i t e}{\text{d")=color(white)("d}} 2 \left(0.92\right) \left(12.46\right)$

${v}^{2} = 2 \left(0.92\right) \left(12.46\right) - {\left(6.5\right)}^{2}$

$v = 4.39$