Question

A card is drawn from a well-shuffled deck of 52 cards. How do you find P(drawing an ace or a 9)?

Answer 1

`P("ace or 9") = 2/13`

Explanation:

There are two possible events that could happen. Either you draw an ace or a 9. There are four aces in a deck of `52` cards as well as `4` of `9`'s in the same deck. The conjunction "or" implies adding up the probabilities of the individual events . Thus,

`P("ace or 9") = 4/52 + 4/52 = 8/52`

Reduced to lowest terms, the answer is equivalent to `2/13`