A certain aircraft has a mass of 300,000 kg. At a certain instant during its landing, its speed is 27.0 m/s. If the braking force is a constant 445,000 N, what is the speed of the airplane 10.0 s later?

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Answer 1 · 2017-03-23T14:10:46

The speed is #=12.2ms^-1#

#vecF=mveca#

#veca=vecF/m#

The deceleration of the plane is

#=-445000/300000=-1.48ms^-2#

Initial speed is #u=27ms^-1#

time #=ts#

Final speed is #v=u+at#

#v=27-1.48*10=12.2ms^-1#