A certain mass of water was heated with 41,840 Joules, raising its temperature from 22.0°C to 28.5°C. What is the mass of the water, in grams?
1 Answer
Mar 31, 2016
1541g
Explanation:
Water specific heat is 4.178 J/g-°K.
The temperature change is 28.5 – 22.0 = 6.5 (because it is a difference, °C or °K doesn't matter)
41840J = 4.178 J/g-°K * Xg * deltaT
Xg = 41840J / (4.178 * 6.5) = 1541g water
