A charge of #24 C# passes through a circuit every #2 s#. If the circuit can generate #8 W# of power, what is the circuit's resistance?

1 Answer
Feb 2, 2016

#R= 1/18 Omega#

Explanation:

First of all calculate the current, then use the power equation to calculate the resistance.

Current #I = 24/2 = 12 C/s# or #12 Amp#

#P=I^2R# where #P# is the power, #I# is the current and #R# is the resistance.

#8 = 12^2R#
#R=8/144 = 1/18 Omega#