# A charge of 24 C passes through a circuit every 9 s. If the circuit can generate 8 W of power, what is the circuit's resistance?

Feb 12, 2016

Use: $P = {I}^{2} R$, where I is the current, and I=charge/time=24C/9s=8/3 Amps. You will find that the resistance, R = $1.125$ Ohms.

#### Explanation:

Use: $P = {I}^{2} R$, where I is the current, and I=charge/time=24C/9s.

Now:
$R = \frac{P}{I} ^ 2$
P=8 Watts

$I = \frac{24 C}{9 s} = \frac{8}{3}$ Amperes

$R = \frac{8}{\frac{8}{3}} ^ 2$ Ohms = $\left(\frac{9}{8}\right)$ Ohms

You will find that the resistance, R = $1.125$ Ohms.