A charge of #35 C# passes through a circuit every #5 s#. If the circuit can generate #42 W# of power, what is the circuit's resistance?

1 Answer
Dec 10, 2016

#R ~~ 0.857" "Omega#

Explanation:

The unit of current, the Ampere, is defined as 1 Coulomb of charge per second, therefore, the current, #I#, in the given circuit is:

#I = (35" "C)/(5" S") = 7 A#

One of the ways to compute power consumed by a circuit is, using the equation:

#P = I^2R#

where I is the current and R is the resistance.

I will assume that you mean that the circuit consumes 42 Watts:

#42 W = (7 A)^2R#

Solve for R:

#R ~~ 0.857" "Omega#