A charge of #36 C# passes through a circuit every #4 s#. If the circuit can generate #81 W# of power, what is the circuit's resistance?

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Answer 1 · 2018-03-31T22:54:58

I got: #1Omega#

Power is related to Tension #V# and Current #I# as:

#P=VI#

Where: #"Current"="Charge"/"Time"=q/t#

so we get:

#P=V*q/t#

with our data:

#81=V36/4#

rearranging:

#V=9V#

From Ohm's Law:

#V=RI#

#R=V/I=9/(36/4)=1Omega#