A charge of 5 C passes through a circuit every 5 s. If the circuit can generate 15 W of power, what is the circuit's resistance?

Oct 3, 2016

$R = 15 \Omega$

Explanation:

$\frac{5 C}{5 s} = 1$ ampere

P = I²R

$15 W = \left(1 A\right)$R

$R = 15 \Omega$