Question

A charge of `6 C` passes through a circuit every `3 s`. If the circuit can generate `4 W` of power, what is the circuit's resistance?

Answer 1

`"The current in the circuit"(I)="Charge passing through it"/"Time"`

`=(6C)/(3s)=2A`

Now `"Power" (P)=I^2xxR`, where R = Resistance

So`R=P/I^2=4/2^2=1Omega`