# A circuit with a resistance of 6 Omega has a fuse with a capacity of 5 A. Can a voltage of 57 V be applied to the circuit without blowing the fuse?

Jan 5, 2016

No, the fuse will blow.

#### Explanation:

Ohm's Law gives us:

$V = I R$

$\therefore I = \frac{V}{R} = \frac{57}{6} = 9.5 \text{A}$

So you can see that too much current will be drawn through the fuse which is only rated at $6 \Omega$ so it will blow.