# A cone has a height of 15 cm and its base has a radius of 9 cm. If the cone is horizontally cut into two segments 6 cm from the base, what would the surface area of the bottom segment be?

$\frac{324}{25} \cdot \pi$
the cone has a gradient of $\frac{5}{3}$ (It goes up 15 in the space of 9)
As y, or it's height is 6, then x, or its radius is $\frac{18}{5}$
${\left(\frac{18}{5}\right)}^{2} \cdot \pi = \frac{324}{25} \cdot \pi$