A container has #12 L# of water in it at #90 ^o C#. An object with a specific heat of #160 (KJ)/(Kg*K)# and a temperature of #250 ^oC# is placed into the container. If the water is completely vaporized, what is the object's mass?

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Answer 1 · 2018-01-08T07:02:29

The mass of the object is #=1.149kg#

The heat is transferred from the hot object to the cold water.

The temperature of the water is #T_w=90^@"C"#

The temperature of the object is #T_o=250^@"C"#

# m_o C_o (DeltaT_o-100) = m_w C_w (100-90)+m_wH_w#

The specific heat of water is #C_w=4.186kJkg^-1K^-1#

The specific heat of the object is #C_o=160"kJ""kg"^-1K^-1#

The heat of vaporisation of water is #H_w=2257"kJ""kg"^-1#

The mass of the object is #m_0=?kg#

The mass of the water is #m_w=12kg#

# m_o *160*(250-100) = 12 *4.186 (100-90)+12*2257 #

#24000m_o=27586#

#m_o=27586/24000=1.149" kg"#