A container has #18 L# of water in it at #20 ^o C#. An object with a specific heat of #350 (KJ)/(Kg*K)# and a temperature of #550 ^oC# is placed into the container. If the water is completely vaporized, what is the object's mass?

Question

342 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-12-28T06:29:05

The mass of the object is #=0.30kg#

The heat is transferred from the hot object to the cold water.

The temperature of the water is #T_w=20^@C#

The temperature of the object is #T_o=550^@C#

# m_o C_o (DeltaT_o-100) = m_w C_w (100-20)+m_wH_w#

The specific heat of water is #C_w=4.186kJkg^-1K^-1#

The specific heat of the object is #C_o=350kJkg^-1K^-1#

The heat of vaporisation of water is #H_w=2257kJkg^-1#

The mass of the object is #m_0=?kg#

The mass of the water is #m_w=18kg#

# m_o 350 (550-100) = 18 *4.186 (100-20)+18*2257#

#157500m_o=46653.8#

#m_o=46653.8/157500=0.30kg#