Question

A container has a volume of `3 L` and holds `2 mol` of gas. If the container is expanded such that its new volume is `13 L`, how many moles of gas must be injected into the container to maintain a constant temperature and pressure?

Answer 1

`=6.67 mol`

Explanation:

By The equation of state for real gas we know

`PV = nRT`

Where
P = Pressure, V = Volume, n = number of moles of gas , T = Absolute temperature of the gas and R = universal gas constant.
In our case P and T are constant in both the case

So `V propn`
Here `V_1=3L and V_2=13L`
`n_1=2mol and n_2 =?`
`n_2/n_1=V_2/V_1=>n_2=n_1xxV_2/V_1=2xx13/3~~8.67mol`

So No of moles of gas injected `=n_2-n_1=8.67-2=6.67 mol`