# A container with a volume of 12 L contains a gas with a temperature of 150^o C. If the temperature of the gas changes to 620 ^o K without any change in pressure, what must the container's new volume be?

#### Answer:

new volume $\approx 17.6 L$

#### Explanation:

Because the pressure don't change
we apply ${V}_{1} / {T}_{1} = {V}_{2} / {T}_{2}$
where V (L), T(K)
Hence $\frac{12}{423} = {V}_{2} / 620$
${V}_{2} = 12 \cdot \frac{620}{423}$
${V}_{2} \approx 17.6 L$